
DBMS -2020 Question &Â Answer
LESSON – 24
āĻāĻ āϞā§āϏāύ⧠āĻāĻŽāϰāĻž DBMS -2020 Question & Answer āϏāĻŽā§āĻĒāϰā§āĻā§ āĻāĻžāύāĻŦāĨ¤ āĻāĻāĻžāύ⧠āĻĒā§āϰāĻĨāĻŽā§ Question āĻāĻā§ āĻĒāϰ⧠Answer āĻāĻā§ āĨ¤ āĻĒā§āϰāĻĨāĻŽā§ āϤā§āĻŽāϰāĻž āĻĒā§āϰāĻļā§āύāĻāĻžāϰ āĻāϰāĻŦā§ āĻāĻŦāĻ āĻĒāϰ⧠āĻāϤā§āϤāϰā§āϰ āϏāĻžāĻĨā§ āĻŽāĻŋāϞāĻŋāϝāĻŧā§ āύāĻŋāĻŦā§ āĨ¤
MCQ QUESTION
āĻŦāĻŋāĻāϞā§āĻĒ āĻāϤā§āϤāϰ āĻā§āϞāĻŋāϰ āĻŽāϧā§āϝ⧠āϏāĻ āĻŋāĻ āĻāϤā§āϤāϰ āĻŦā§āĻā§ āύāĻŋāϝāĻŧā§ āϞā§āĻāĻ- 1.āύāĻŋāĻŽā§āύāϞāĻŋāĻāĻŋāϤ āĻā§āύāĻāĻŋ āĻāĻāĻāĻŋ relation-āĻ tuple āĻā§ āϏā§āĻŦāϤāύā§āϤā§āϰāĻāĻžāĻŦā§ āĻļāύāĻžāĻā§āϤ āĻāϰāϤ⧠āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻāϰāĻž āϝāĻžāĻŦā§ āύāĻž ? (a)Super Key (b) Primary Key (c) Candidate Key (d) Foreign Key â
2. E-R Diagram-āĻ Attribute āĻā§āύ Symbol āĻĻā§āĻŦāĻžāϰāĻž āĻāĻŋāĻšā§āύāĻŋāϤ āĻšāϝāĻŧ ? (a)    â                                 (b)     âĻ                               (c)    â                       (d)     â˛Â                           Â
3. āύāĻŋāĻŽā§āύāϞāĻŋāĻāĻŋāϤ āĻā§āύāĻāĻŋ Database constraint ? (a)Primary Key (b) Foreign Key (c) a āĻ b āĻāĻāϝāĻŧāĻ (d) āĻāĻĻā§āϰ āĻā§āύā§āĻāĻŋ āύāϝāĻŧ
4. Data Dictionary âāϰ āĻāĻžāĻ āĻšāϞ â (a)Meta Data āϏāĻā§āĻāϝāĻŧ āĻāϰāĻž (b) anomalies āĻĻā§āϰ āĻāϰāĻžÂ (c) Data āĻā§ āĻ āύā§āϝ āĻāĻžāώāĻžāϝāĻŧ āĻĒāϰāĻŋāĻŦāϰā§āϤāύ āĻāϰāĻž (d) āϏāĻŦāĻāĻāĻŋ āĻ āĻŋāĻ
5. āύā§āĻā§āϰ āĻā§āύāĻāĻŋ relational algebra āĻāϰ operation āύāϝāĻŧ? (a)Selection (b) Production (c) Set Difference (d) Union
6. Record-āĻāϰ āĻ āĻĒāϰ āύāĻžāĻŽ āĻšāϞ â
(a) Tuple (b) Degree (c) Attribute (d) Cardinality
MCQ Answer
1.āύāĻŋāĻŽā§āύāϞāĻŋāĻāĻŋāϤ āĻā§āύāĻāĻŋ āĻāĻāĻāĻŋ relation-āĻ tuple āĻā§ āϏā§āĻŦāϤāύā§āϤā§āϰāĻāĻžāĻŦā§ āĻļāύāĻžāĻā§āϤ āĻāϰāϤ⧠āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻāϰāĻž āϝāĻžāĻŦā§ āύāĻž ? (a)Super Key (b) Primary Key (c) Candidate Key (d) Foreign Key
Ans: (d) Foreign Key
2. E-R Diagram-āĻ Attribute āĻā§āύ Symbol āĻĻā§āĻŦāĻžāϰāĻž āĻāĻŋāĻšā§āύāĻŋāϤ āĻšāϝāĻŧ ? (a)    â                                 (b)     âĻ                               (c)    â    (āĻāĻĒāĻŦā§āϤ)               Â
(d)     â˛Â        Â
Ans: (C) â(āĻāĻĒāĻŦā§āϤ)
3. āύāĻŋāĻŽā§āύāϞāĻŋāĻāĻŋāϤ āĻā§āύāĻāĻŋ Database constraint ? (a)Primary Key (b) Foreign Key (c) a āĻ b āĻāĻāϝāĻŧāĻ (d) āĻāĻĻā§āϰ āĻā§āύā§āĻāĻŋ āύāϝāĻŧ
Ans: (d) āĻāĻĻā§āϰ āĻā§āύā§āĻāĻŋ āύāϝāĻŧ
4. Data Dictionary âāϰ āĻāĻžāĻ āĻšāϞ â (a)Meta Data āϏāĻā§āĻāϝāĻŧ āĻāϰāĻž (b) anomalies āĻĻā§āϰ āĻāϰāĻž (c) Data āĻā§ āĻ āύā§āϝ āĻāĻžāώāĻžāϝāĻŧ āĻĒāϰāĻŋāĻŦāϰā§āϤāύ āĻāϰāĻž (d) āϏāĻŦāĻāĻāĻŋ āĻ āĻŋāĻ
Ans: Meta Data āϏāĻā§āĻāϝāĻŧ āĻāϰāĻž
5. āύā§āĻā§āϰ āĻā§āύāĻāĻŋ relational algebra āĻāϰ operation āύāϝāĻŧ? (a)Selection (b) Production (c) Set Difference (d) Union
Ans: (b) Production
6. Record-āĻāϰ āĻ āĻĒāϰ āύāĻžāĻŽ āĻšāϞ â (a)Tuple (b) Degree (c) Attribute (d) Cardinality
Ans: Tuple
Short Question
āύāĻŋāĻā§āϰ āĻĒā§āϰāĻļā§āύāĻā§āϞāĻŋāϰ āϏāĻāĻā§āώāĻŋāĻĒā§āϤ āĻāϤā§āϤāϰ āĻĻāĻžāĻāĻ- 1.Database Instance āĻŦāϞāϤ⧠āĻāĻŋ āĻŦā§āĻā§ ?
2.Network Data Model āĻāϰ āĻāĻāĻāĻŋ āĻŦā§āĻļāĻŋāώā§āĻā§āϝ āĻāϞā§āϞā§āĻ āĻāϰ⧠āĨ¤
3.Normalization āĻāϰ āϏāĻāĻā§āĻāĻž āĻĻāĻžāĻ āĨ¤
4.āĻā§āύ⧠relation āĻāϰ degree āĻŦāϞāϤ⧠āĻā§ āĻŦā§āĻā§ ?
Short Question Answer
āύāĻŋāĻā§āϰ āĻĒā§āϰāĻļā§āύāĻā§āϞāĻŋāϰ āϏāĻāĻā§āώāĻŋāĻĒā§āϤ āĻāϤā§āϤāϰ āĻĻāĻžāĻāĻ- 1.Database Instance āĻŦāϞāϤ⧠āĻāĻŋ āĻŦā§āĻā§ ?
Ans: āĻĄā§āĻāĻžāĻŦā§āϏ āϏāĻŋāϏā§āĻā§āĻŽā§ āĻā§āύ⧠āύāĻŋāϰā§āĻĻāĻŋāώā§āĻ āĻŽā§āĻšā§āϰā§āϤ⧠āĻĒā§āϰāĻžāĻĒā§āϤ āĻĄā§āĻāĻžāϰ āϏāĻŽāĻā§āϰ āĻāĻŋāϤā§āϰāĻāĻŋāĻā§ āĻāĻ āĻŽā§āĻšā§āϰā§āϤā§āϰ āĻāύāϏā§āĻā§āϝāĻžāύā§āϏ āĻŦāϞ⧠āĨ¤ āϏāĻŽāϝāĻŧā§āϰ āϏāĻžāĻĨā§ āϏāĻžāĻĨā§ āĻĄā§āĻāĻžāĻŦā§āϏā§āϰ āϰā§āĻāϰā§āĻĄā§āϰ āϏāĻāĻā§āϝāĻž āĻŦāĻžāĻĄāĻŧāϤ⧠āĻŦāĻž āĻāĻŽāϤ⧠āĻĒāĻžāϰ⧠āϤāĻžāĻ āϏāĻŽāϝāĻŧā§āϰ āϏāĻžāĻĨā§ āϏāĻžāĻĨā§ āĻĄā§āĻāĻžāĻŦā§āϏ āĻāύāϏā§āĻā§āϝāĻžāύā§āϏ āĻĒāϰāĻŋāϰā§āĻŦāϤāύ āĻšāϝāĻŧ āĨ¤
2. Network Data Model āĻāϰ āĻāĻāĻāĻŋ āĻŦā§āĻļāĻŋāώā§āĻā§āϝ āĻāϞā§āϞā§āĻ āĻāϰ⧠āĨ¤
Ans: āĻšāĻžāϝāĻŧāĻžāϰāĻžāϰāĻāĻŋāĻā§āϝāĻžāϞ āĻŽāĻĄā§āϞā§āϰ āĻāύā§āύāϤ āϰā§āĻĒ āĻšāϞ āύā§āĻāĻāϝāĻŧāĻžāϰā§āĻ āĻŽāĻĄā§āϞ āĨ¤
âĸ āĻāĻ āĻŽāĻĄā§āϞ⧠āĻĒā§āϝāĻžāϰā§āύā§āĻ āĻ āĻāĻžāĻāϞā§āĻĄ āϏāĻŦ āĻā§āĻŦāĻŋāϞā§āϰ āϏāĻžāĻĨā§ āϏāĻŦ āĻā§āĻŦāĻŋāϞā§āϰ āϞāĻŋāĻā§āĻ āĻĨāĻžāĻā§ āĨ¤
âĸ āĻāĻ āĻŽāĻĄā§āϞ⧠āϤāĻŋāύāĻāĻŋ āϏāĻžāϧāĻžāϰāĻŖ āĻāĻĒāĻžāĻĻāĻžāύ āĻšāϞ āĻ- āϰā§āĻāϰā§āĻĄ āĻāĻžāĻāĻĒ, āĻĄā§āĻāĻž āĻāĻāĻā§āĻŽ āĻāĻŦāĻ āϞāĻŋāĻā§āĻ āĨ¤
3. Normalization āĻāϰ āϏāĻāĻā§āĻāĻž āĻĻāĻžāĻ āĨ¤
Ans: Database āĻāϰ āϰāĻŋāϞā§āĻļāύ⧠āĻĄā§āĻāĻžāϰ āĻĒā§āύāϰāĻžāĻŦā§āϤā§āϤāĻŋ (Redundancy) āĻāĻŽ āĻāϰāĻžāύāϰ āĻāύā§āϝ āĻā§āĻŦāĻŋāϞ/āϰāĻŋāϞā§āĻļāύ āĻā§ āĻāĻāĻžāϧāĻŋāĻ āĻā§āĻ āĻā§āĻ āĻā§āĻŦāĻŋāϞ⧠āĻŦāĻž āϰāĻŋāϞā§āĻļāύ⧠āĻāĻžāĻā§āĻāĻžāϰ āĻĒāĻĻā§āϧāϤāĻŋ āĻā§ Normalization āĻŦāϞ⧠āĨ¤
āĻāϰ āĻŦāĻŋāĻāύā§āύ āϧāĻžāĻĒāĻā§āϞāĻŋ āĻšāϞ â 1st Normal Form, 2nd Normal Form, 3rd Normal Form, 4th Normal Form, 5th Normal Form āĻāĻŦāĻ Domain Key Normal Form āĨ¤
4. āĻā§āύ⧠relation āĻāϰ degree āĻŦāϞāϤ⧠āĻā§ āĻŦā§āĻā§ ?
Ans: āĻā§āύ⧠āϰāĻŋāϞā§āĻļāύā§āϰ āĻĢāĻŋāϞā§āĻĄ āĻŦāĻž āĻāϞāĻžāĻŽ āϏāĻāĻā§āϝāĻž āĻā§ āĻĄāĻŋāĻā§āϰāĻŋ āĻŦāϞ⧠āĨ¤ āϝā§āĻŽāύ â Student (Name, Roll, Mobile_No, Marks) āϰāĻŋāϞā§āĻļāύ⧠āĻĄāĻŋāĻā§āϰāĻŋ āĻšāϞ 4 āĨ¤ āĻāĻžāϰāύ āĻāĻāĻžāύ⧠āĻāĻžāϰāĻāĻŋ āĻ ā§āϝāĻžāĻā§āϰāĻŋāĻŦāĻŋāĻāĻ āĻāĻā§ āĨ¤
Part-A Question No-1
āύāĻŋāĻā§āϰ āĻĒā§āϰāĻļā§āύāĻā§āϞāĻŋāϰ āĻāϤā§āϤāϰ āĻĻāĻžāĻāĻ 1. āύā§āĻā§āϰ table  āϞāĻā§āώ āĻāϰā§-
| E_ID | Nam | City | Age |
| C1 | A.Chatterjee | Chennai | 51 |
| C2 | S. Koner | Mumbai | 49 |
| C3 | A. Mitra | Delhi | 55 |
| C4 | B. Roy | Bandalore | 50 |
āύāĻŋāĻŽā§āύāϞāĻŋāĻāĻŋāϤ āĻāĻžāĻāĻā§āϞāĻŋ āĻāϰāĻžāϰ āĻāύā§āϝ SQL query āϞā§āĻā§ āĻāĻŦāĻ Output āĻĻā§āĻāĻžāĻ â
(a)āϏāĻŽāϏā§āϤ Customer āĻĻā§āϰ City āĻĻā§āĻāĻžāĻ āϝāĻžāĻĻā§āϰ Age 51 āĻāϰ āĻāĻŽ āĨ¤
(b)āϏā§āĻ āϏāĻŽāϏā§āϤ Customer āĻĻā§āϰ āύāĻžāĻŽ āĻā§āĻā§ āĻŦā§āϰ āĻāϰ⧠āϝāĻžāϰāĻž Delhi āĻŦāĻž Mumbai City āϤ⧠āĻŦāϏāĻŦāĻžāϏ āĻāϰ⧠āĨ¤ āĨ¤
(c)āϏāĻŽāϏā§āĻ¤Â Customer āĻĻā§āĻ°Â record āĻā§āϞāĻŋ āϤāĻžāĻĻā§āϰ age āĻāϰ Deascending order āĻ āϏāĻžāĻāĻžāĻ āĨ¤
Part-A Question No-1 Answer
āύāĻŋāĻŽā§āύāϞāĻŋāĻāĻŋāϤ āĻāĻžāĻāĻā§āϞāĻŋ āĻāϰāĻžāϰ āĻāύā§āϝ SQL query āϞā§āĻā§ āĻāĻŦāĻ Output āĻĻā§āĻāĻžāĻ â (a)āϏāĻŽāϏā§āϤ Customer āĻĻā§āϰ City āĻĻā§āĻāĻžāĻ āϝāĻžāĻĻā§āϰ Age 51 āĻāϰ āĻāĻŽ āĨ¤
Ans: Select City From Customer Where Age<51; (a)āϏā§āĻ āϏāĻŽāϏā§āϤ Customer āĻĻā§āϰ āύāĻžāĻŽ āĻā§āĻā§ āĻŦā§āϰ āĻāϰ⧠āϝāĻžāϰāĻž Delhi āĻŦāĻž Mumbai City āϤ⧠āĻŦāϏāĻŦāĻžāϏ āĻāϰ⧠āĨ¤
Ans: Select Name From Customer Where City IN(âDelhiâ,âMumbaiâ); (a)āϏāĻŽāϏā§āϤ Customer āĻĻā§āϰ record āĻā§āϞāĻŋ āϤāĻžāĻĻā§āϰ age āĻāϰ Deascending order āĻ āϏāĻžāĻāĻžāĻ āĨ¤
Ans: Select * From Customer Order By Age DESC;
Part-A Question No-2/or
āĻ āĻĨāĻŦāĻž (a)Relational Algebra-āϰ Set difference operation āĻāĻŋ āĻāĻĻāĻžāĻšāϰāύ āϏāĻš āĻŦā§āϝāĻžāĻā§āϝāĻž āĻāϰ⧠āĨ¤
(b)Distinct āĻāĻŦāĻ Drop Command āĻāϰ Function āĻāĻŦāĻ Syntax āϞā§āĻā§ āĨ¤
(c)DDL āĻāϰ āϝ⧠āĻā§āύ⧠āĻĻā§āĻāĻŋ āĻāĻĻāĻžāĻšāϰāĻŖ āĻĻāĻžāĻ āĨ¤
Part-A, Q.No-2/or Answer
(a)Relational Algebra-āϰ Set difference operation āĻāĻŋ āĻāĻĻāĻžāĻšāϰāύ āϏāĻš āĻŦā§āϝāĻžāĻā§āϝāĻž āĻāϰ⧠āĨ¤
āĻāĻāĻŋ āĻāĻāĻāĻŋ āĻŦāĻžāĻāύāĻžāϰāĻŋ āϏā§āĻ āĻ āĻĒāĻžāϰā§āĻāϰ āĨ¤ āϝāĻā§ â-â āĻāĻŋāĻšā§āύ āĻĻā§āĻŦāĻžāϰāĻž āĻĒā§āϰāĻāĻžāĻļ āĻāϰāĻž āĻšāϝāĻŧ āĨ¤ āĻĒā§āϰāĻĨāĻŽ āϰāĻŋāϞā§āĻļāύ āĻĨā§āĻā§ āĻĻā§āĻŦāĻŋāϤā§āϝāĻŧ āϰāĻŋāϞā§āĻļāύ āĻĄāĻŋāĻĢāĻžāϰā§āύā§āϏ āĻāϰāϞ⧠āĻĻā§āĻŦāĻŋāϤā§āϝāĻŧ
āϰāĻŋāϞā§āĻļāύā§āϰ āϝ⧠āĻāĻžāĻĒāϞ āĻā§āϞāĻŋ āĻĒā§āϰāĻĨāĻŽ āϰāĻŋāϞā§āĻļāύ āĻĨāĻžāĻā§ āϏā§āĻā§āϞāĻŋāĻā§ āĻŦāĻžāĻĻ āĻĻāĻŋāϤ⧠āĻšāϝāĻŧ āĨ¤ āĻāĻāĻ āĻāĻžāĻŦā§ āĻĻā§āĻŦāĻŋāϤā§āϝāĻŧ āϰāĻŋāϞā§āĻļāύ āĻĨā§āĻā§ āĻĒā§āϰāĻĨāĻŽ āϰāĻŋāϞā§āĻļāύ āĻĄāĻŋāĻĢāĻžāϰā§āύā§āϏ āĻāϰāϞ⧠āĻĒā§āϰāĻĨāĻŽ āϰāĻŋāϞā§āĻļāύā§āϰ āϝ⧠āĻāĻžāĻĒāϞ āĻā§āϞāĻŋ āĻĻā§āĻŦāĻŋāϤā§āϝāĻŧ āϰāĻŋāϞā§āĻļāύ āĻĨāĻžāĻā§ āϏā§āĻā§āϞāĻŋāĻā§ āĻŦāĻžāĻĻ āĻĻāĻŋāϤ⧠āĻšāϝāĻŧ
āϝā§āĻŽāύ â āĻĻā§āĻāĻŋ āϰāĻŋāϞā§āĻļāύ A – B āĻāĻŦāĻ B â A āĻāĻ°Â āϏā§āĻ āĻĄāĻŋāĻĢāĻžāϰā§āύā§āϏ  āĻ āĻĒāĻžāϰā§āĻļāĻ¨Â āύāĻŋāĻā§ āĻĻā§āĻāĻžāύ āĻšāϞ āĨ¤
| A | |
| Roll | Name |
| 1 | Roni |
| 2 | Joni |
| 3 | Boni |
| B | |
| Roll | Name |
| 4 | Moni |
| 2 | Joni |
| 5 | Toni |
| A – B | |
| Roll | Name |
| 1 | Roni |
| 3 | Boni |
| B – A | |
| Roll | Name |
| 4 | Moni |
| 5 | Toni |
āĻ āĻĨāĻŦāĻž
(b) Distinct āĻāĻŦāĻ Drop Command āĻāϰ Function āĻāĻŦāĻ Syntax āϞā§āĻā§ āĨ¤
āĻāĻ āϏā§āĻā§āĻāĻŽā§āύā§āĻ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻāϰ⧠āĻā§āύ⧠āĻā§āĻŦāĻŋāϞā§āϰ āĻāĻ āĻŦāĻž āĻāĻāĻžāϧāĻŋāĻ āĻĄā§āϞā§āĻĒāĻŋāĻā§āĻ āϰ⧠āĻā§ āĻŦāĻžāĻĻ āĻĻāĻŋāϝāĻŧā§ āĻĻā§āĻāĻžāύāϰ āĻāύā§āϝ Distinct āĻā§āϞāĻ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻāϰāĻž āĻšāϝāĻŧ āĨ¤
| Roll | Name | Class | Address | Marks |
| 1 | Rina | XII | Jiaganj | 450 |
| 2 | Bina | XI | Lalbag | 400 |
| 3 | Tina | XII | Jiaganj | 425 |
| 4 | Dona | XI | Lalbag | 400 |
| 5 | Mona | XII | Berhampore | 421 |
āϝā§āĻŽāύ â āĻāĻĒāϰā§āϰ Student āĻā§āĻŦāĻŋāϞ āĻĨā§āĻā§ āĻāĻžāύāϤ⧠āĻāĻžāĻ āϝ⧠āĻā§āĻŦāĻŋāϞ⧠āĻā§āύ āĻā§āύ āĻļāĻšāϰā§āϰ āύāĻžāĻŽ āĻāĻā§ āĨ¤
SELECT DISTINCT Address FROM Student;
āϤāĻžāĻšāϞ⧠āĻāϤā§āϤāϰ āĻĒāĻžāĻāϝāĻŧāĻž āϝāĻžāĻŦā§
| Address |
| Jiaganj |
| Lalbag |
| Berhampore |
(c) DDL āĻāϰ āϝ⧠āĻā§āύ⧠āĻĻā§āĻāĻŋ āĻāĻĻāĻžāĻšāϰāĻŖ āĻĻāĻžāĻ āĨ¤
Create: āĻāĻ āĻāĻŽā§āϝāĻžāύā§āĻĄ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻāϰ⧠āĻĄā§āĻāĻžāĻŦā§āϏ āĻā§āĻŦāĻŋāϞ āϤā§āϰāĻŋ āĻāϰāĻž āϝāĻžāϝāĻŧ āĨ¤
Syntax : CREATE TABLE <table name> (Field_Name1 Data_Type, Field_Name2 Data_TypeâĻâĻ..)
āϝā§āĻŽāύ Student āύāĻžāĻŽā§āϰ āĻāĻāĻāĻŋ āĻā§āĻŦāĻŋāϞ āϤā§āϰāĻŋ āĻāϰāϤ⧠āĻšāĻŦā§ āϝā§āĻāĻžāύ⧠Roll, Name, Address,Marks āύāĻžāĻŽā§ āĻāĻžāϰāĻāĻŋ āĻĢāĻŋāϞā§āĻĄ āĻĨāĻžāĻāĻŦā§ āϤāĻžāϰ āĻāĻŽāĻžāύā§āĻĄ āĻšāϞ
CREATE TABLE Student(Roll int, Name char(20), Address char(30), Marks int);
ALTER : āĻāĻ āĻāĻŽāĻžāύā§āĻĄā§āϰ āϏāĻžāĻšāĻžāϝā§āϝ⧠āĻĄā§āĻāĻžāĻŦā§āϏ āĻā§āĻŦāĻŋāϞā§āϰ āĻāĻ āύ āĻĒāϰāĻŋāĻŦāϰā§āϤāύ āĻāϰāĻž āϝāĻžāϝāĻŧ āĨ¤ āĻ āϰā§āĻĨāĻžā§ āĻā§āĻŦāĻŋāϞ⧠āύā§āϤāύ āĻĢāĻŋāϞā§āĻĄ āϝā§āĻā§āϤ āĻāϰāĻž, āĻā§āύ⧠āĻĢāĻŋāϞā§āĻĄāĻā§ āĻŽā§āĻā§āĻĢā§āϞāĻž, āĻā§āύ⧠āĻĢāĻŋāϞā§āĻĄā§āϰ āύāĻžāĻŽ āĻāĻŦāĻ āĻĄā§āĻāĻž āĻāĻžāĻāĻĒ āĻĒāϰāĻŋāĻŦāϰā§āϤāύ āĻāϤā§āϝāĻžāĻĻāĻŋ āĻŦāĻŋāĻāĻŋāύā§āύ āĻāĻžāĻ āĻāϰāĻž āϝāĻžāϝāĻŧ āĨ¤
āϝā§āĻŽāύāĻ Student āĻā§āĻŦāĻŋāϞ⧠MobileNo āύāĻžāĻŽā§ āĻāĻāĻāĻŋ āύā§āϤāύ āĻĢāĻŋāϞā§āĻĄāϝā§āĻā§āϤ āĻāϰāĻžāϰ āĻāĻŽāĻžāύā§āĻĄ āĻšāϞāĻ
ALTER TABLE Student ADD(Mobile int);
